43 40 13 400 231 2232 2 12 2S 213 223 2 33 243 21y 22 4 234

43 40 13 400 231 2232 2 12 2.S 213 223 2 33 243 21y 22 4 234 2 23 S 3 2y5 23 Sida vi 211, 23 212, 222, 732, 2Vz 213 223 , 233, 213 224, 23Y 219, 24 225, 23s 215, 24S 226. 23 SecH.

Solution

Note...

1)Area of trapizoidal = (a+b)×(d÷2)

Where\'

a = base width of the trapizoidal

b= upper base of the trapizoidal

d = height of the trapizoidal

And volume = area × length

2) area of rectangle= length × width

Now,

Find the volume of section using this formula