1 In an experiment C D are independent events with probabili
1) In an experiment, C, D are independent events with probabilities P[ intersection D] = 1/3, P[C] = 1/2
a) Find P[D], P[C intersection D^(c)], P[C^(c) intersection D^(c)]
b) Find P[C union D] and P[C union D^(c)]
c) Are C and D^(c) independent?
2) For the independent events A and B, prve that
a) A and B^(c) are independent
b) A^(c) and B are independent
c) A^(c) and B^(c) are independent
Solution
1.)
a.) C and D are independent means P(C intersection D) = P(C)*P(D)
So 1/3 = (1/2)*P(D)
So P(D) = 2/3
P(C intersection D^c) = P(C)*(1-P(D)) = (1/2)*(1/3) = 1/6
P(C^c intersection D^c) = (1-P(C))*(1-P(D)) = (1/2)*(1/3) = 1/6
b.) P(C union D) = P(C) + P(D) - P(C intersection D) = 1/2 + 2/3 - (1/2)*(2/3) = 5/6
P(C union D^c) = P(C) + 1 - P(D) - P(C intersection D^c) = 1/2 + 1/3 - 1/6 = 2/3
c.) P(C intersection D^c) = P(C)*P(D^c) = 1/6
So C and D^c are independent
2.) P(A intersection B) = P(A)*P(B)
a.) P(A)P(B^c) = P(A)(1-P(B)) = P(A) - P(A intersection B)
= P(A intersection B^c)
So A and B^c are independent.
b.) P(A^c)P(B) = (1-P(A))P(B) = P(B) - P(A intersection B)
= P(A^c intersection B)
So A^c and B are independent.
c.) P(A^c)P(B^c) = (1-P(A))(1-P(B)) = 1 - P(A) - P(B) + P(A intersection B) = 1 - P(A union B) = P((A union B)^c)
= P(A^c intersection B^c)
So A^c and B^c are independent.
![1) In an experiment, C, D are independent events with probabilities P[ intersection D] = 1/3, P[C] = 1/2 a) Find P[D], P[C intersection D^(c)], P[C^(c) intersec 1) In an experiment, C, D are independent events with probabilities P[ intersection D] = 1/3, P[C] = 1/2 a) Find P[D], P[C intersection D^(c)], P[C^(c) intersec](/WebImages/1/1-in-an-experiment-c-d-are-independent-events-with-probabili-966599-1761495092-0.webp)