Please provide with step by step solution thank you Accepted

Please provide with step by step solution thank you!

Accepted characters: numbers, decimal point markers (period or comma), sign indicators (-), spaces (e.g., as thousands separator, 5 000), \"E\" or \"e\" (used in scientific notation). Complex numbers should be in the form (a + bi) where \"a\" and \"b\" need to have explicitly stated values. For example: {1+1i} is valid whereas {1 +i} is not. {0+9i} is valid whereas {9i} is not. Given: All components are ideal. V_m = 240 Vrms at 120 Flz Output Resistor R = 10 Ohm Determine the average of the output voltage V_0. Determine the rms of the of output voltage v_0. Determine the average load current through R. Determine the average power absorbed by the load R. Determine the power factor of the circuit.

Solution

From the above circuitry it is obvious that Half wave rectification is going on for the volate provided.

For the Half wave rectifier, the Average voltage = Vavg= 0.318Vpk

a) Given, Vrms = 240Volts at 120Hz.

Now Vpk = sqrt2 X Vrms = 240 X 1.41421 = 339.411 Volts

Therefore Vavg is 0.31830988 x 339.411 = 108.0378768 Volts

b) Vrms of output = Vrms= Vpk/2 = 339.411/2 = 169.7055 Volts

c) Load current through R is Vavg / R = 108.0378768 / 10 = 10.803787 Amperes

d) Average power is Vavg (Full wave) X Iavg = 266.5 x 10.803787 = 2879.809 Watts