Engineering dynamics practice problem please write clearly s

Engineering dynamics practice problem please write clearly so I can understand and follow the process

sphere moving horizontall right with an initial velocity of 5 m/s strikes the lower end of aan 10-kg rigid rod AB. The rod is suspended from a A and initially at owing coefficient of restitution between the rod and the hinge at determine the ang ular velocity of the is 75. rod and the velocity of the sphere immediately after the impact. I m

Solution

Given,

M_B = 2

M_R = 10

V_B1 = 5

L_R = 1.2

Coefficient of restriction ( C ) = 0.75

Appling conservation of momentum in x direction

M_B*V_B1 = M_B*V_B2 + M_R*V_R2

2*5 = 2*V_B2 + 10*V_R2            --- (a)

C = V_B1 / ( V_R2 – V_B2 )

0.75 = 5 / ( V_R2 – V_B2 )          ------ (b)

Solving equation a & b , we get

V_R2 = 1.945

V_B2 = -4.722

= 1.945/1.2 = 1.621