600 a Find the resistance across a 110 cm2 section of the s

600 .

(a) Find the resistance across a 11.0 cm² section of the skin.


(b) Find the resistivity of the skin, assuming it is 1.04 mm thick.


(c) Suppose the area of contact of each hand with a conductor is reduced to 1.11 cm². Find the resistance between the hands.

If someone can please explain and figure this problem out for me because me, and 5 other people have all attempted to solve it.

For part A I did 11,000=2R+600 ohm. The answer I got was 5,200 ohm and it was wrong. I also tried making it negative but it was still wrong.

For part B I used the equation R=pL/A
R=(5200)(11)/.104
The answer I got for this one 5500 ohm*m

Please help

Solution

1.
the ressitance is,

    R = Rb + 2Rs
   Rs = (R-Rb)/2
   Rs = (1.07 * 10^4 -600) /2
= 5050

2.
the resistivity: = (Rs*A)/L = (5050*11*10^-4) / (1.04 * 10^-3) = 5341.3 -m

3.
Rs₂ / Rs = A/A₂
       Rs₂ = Rs*A/A₂ = 5050 * 11/1.11 = 50045.04

hence, the resistance is,

       R2 = Rb + 2*Rs2 = 600 + 2*50045.04 = 100690 = 10.07x10^4