the second part pls if cos theta 23 and tan theta is 0 find
the second part pls
if cos theta =-2/3 and tan theta is > 0, find sin theta and the other ones below it
Solution
cos=-2/3 <0, tan >0
=> is in third quadrant
=>sin <0
now
cos =adjacent side/hypotenuse= -2/5
hypotenuse2=opposite side2+ adjacent side2
52=opposite side2+22
25=opposite side2+4
opposite side2=21
opposite side=21
sin =opposite side/hypotenuse
sin =-21/5
1)sin(/2 -)
=cos
=-2/5
2)cos(+)
=-cos
=2/5
3)sin(-)
=sin
=-21/5
4)cos(2) =2cos2 -1
cos(2) =2(2/5)2 -1
cos(2) =(8/25) -1
cos(2) =(-17/25)
5)sin(2)=2sincos
sin(2)=2(-21/5)(-2/5)
sin(2)=421/25
