A C program is required to calculate the quadratic equation

A C program is required to calculate the quadratic equation, but which two solutions are given by the formula: x1,2= b±b 24 ac/ 2a (1)

it must use a function called CorrectSolutions() that is used to compute the real solutions of the variables represented by the quadratic equations

it also must use : int computeSolutions(double a, double b, double c, double* px1, double* px2);

if b 24ac<0 then the solutions are complex numbers (i.e. not real) and the function returns 0. *px2 and *px2 are set to 0. •

if b 24ac=0 then x1=x2 and the function returns 1, after writing in *px1 the value of solution x1 and in *px2 the value of x2 (these are equal). •

if b 24ac>0 then the solutions are distinct and the function returns 2, after writing in *px1 the value of x1 and in *px2 the value of x2.

a function named WriteCoefficients (double* pa, double* pb, double* pc) which reads from the terminal a,b and c

lastly, the main() function that reads in a loop sequences of 3 coefficients in local variables a, b, c using the readCoefficients() function as long as the user enters three numbers

output supposed to look like :

1 2 1 -- 1 real solution: x1=x2=-1.00000 3 0 1 -- no real solutions

3 0 -1 -- 2 real solutions: x1=-0.57735 x2=0.57735

Solution

#include<stdio.h>
#include<math.h>
int CorrectSolutions(double a, double b, double c, double* px1, double* px2,int determinant);
int computeSolutions(double a, double b, double c, double* px1, double* px2);
int WriteCoefficients(double* pa, double* pb, double* pc);
void readCoefficients();
int main()
{
  
   readCoefficients();

}

void readCoefficients()
{
   char ch;
   double a, b, c, root1,root2, realPart, determinant,imaginaryPart,x1,x2;
   int ret;

   do
   {
       WriteCoefficients(&a,&b,&c);
       ret = computeSolutions(a,b,c,&x1,&x2);
       CorrectSolutions(a,b,c,&x1,&x2,ret);
   switch(ret)
   {
   case 0:
       printf(\"Solutions are complex numbers \ \");
      
       /*realPart = -b/(2*a);
imaginaryPart = sqrt(-determinant)/(2*a);
printf(\"root1 = %.2lf+%.2lfi and root2 = %.2f-%.2fi\", realPart, imaginaryPart, realPart, imaginaryPart);*/
       break;
   case 1:
       printf(\"Value of px1 = px2 = %lf \ \",x1);
       break;
   case 2:
       printf(\"the solutions are distinct \ \");
       printf(\"px1= %lf px2= %lf\ \",x1, x2);
       break;
   default:
       break;
   }
       printf(\"Want to continue or enter q to quit \ \");
       fflush(stdin);
       scanf(\"%c\",&ch);
   }while(ch!=\'q\');
   printf(\"Quitting.....\ \");
   return;
}

int WriteCoefficients(double* pa, double* pb, double* pc)
{
   printf(\"Enter the coefficients a, b , c : \");
   scanf(\"%lf%lf%lf\",pa,pb,pc);
   return 0;
}

int computeSolutions(double a, double b, double c, double* px1, double* px2)
{
   double determinant,root1, root2;

   determinant = b*b-4*a*c;

// condition for real and different roots
if (determinant > 0)
{
        return 2;
}
   else if (determinant == 0)
{
return 1;
}

// if roots are not real
else
{
return 0;
}

  
}

int CorrectSolutions(double a, double b, double c, double* px1, double* px2,int ret)
{
   double realPart, imaginaryPart, determinant;

   determinant = b*b-4*a*c;

   if( ret > 0 )
   {
       if (ret == 1)
       {
           *px1 = *px2 = -b/(2*a);
             
       }
       else
       {
           *px1 = (-b+sqrt(determinant))/(2*a);
           *px2 = (-b-sqrt(determinant))/(2*a);
       }
   }
   else
{
*px1 = 0;
       *px2 = 0;
       //realPart = -b/(2*a);
       //imaginaryPart = sqrt(-determinant)/(2*a);
       printf(\"no real solutions\ \");
       //printf(\"x1 = %0.2lf+%0.5lfi and x2 = %.2f-%0.5fi\", realPart, imaginaryPart, realPart, imaginaryPart);
   //printf(\"x1 = %0.5lf and x2 = %0.5f\", realPart, imaginaryPart, realPart, imaginaryPart);
   }
   return 0;
}