Engineers are evaluating the installation of a wind turbine

Engineers are evaluating the installation of a wind turbine farm in a location where the average wind speed is 25.8 m/s. What is the kinetic energy s of the wind when traveling that fast, in kJ/kg? kJ/kg

Solution

>> As, Kinetic Energy = (1/2)m*V²

So, Kinetic Energy per unit Mass = (1/2)*V²

As, V = Average Velocity of Wind = 25.8 m/s

>> So, putting all values in above equation,

Kinetic Energy = (1/2)*25.8² = 332.82 J/Kg

or, Kimetic Energy= 0.333KJ/Kg ..... ANSWER.....