A company hopes to improve customer satisfaction setting a g

A company hopes to improve customer satisfaction, setting a goal of no more than 5% negative comments. A random survey of 350 customers found only 14 with complaints. Does this provide evidence at the 10% significance level that the company has reached its goal of decreasing the percentage of complaints?

Solution

The test hypothesis:

Ho: p=0.05 (i.e. null hypothesis)

Ha: p<0.05 (i.e. alternative hypothesis)

The test statistic is

Z=(phat-p)/sqrt(p*(1-p)/n)

=(14/350-0.05)/sqrt(0.05*0.95/350)

=-0.86

It is a left-tailed test.

Given a=0.1, the critical value is Z(0.1) =-1.28 (from standard normal table)

The rejection region is if Z<-1.28, we reject the null hypothesis.

Since Z=-0.86 is larger than -1.28, we do not reject the null hypothesis.

So we can not conclude that the company has reached its goal of decreasing the percentage of complaints

A company hopes to improve customer satisfaction, setting a goal of no more than 5% negative comments. A random survey of 350 customers found only 14 with compl

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