A mailorder computer business has six telephone lines Let X
A mail-order computer business has six telephone lines. Let X denote the number of lines in use at a specified time. Suppose the pmf of X is as given in the accompanying table.
Calculate the cdf F(x).
calculate the probabilities of the events given below. (a) {at most three lines are in use}
(b) {fewer than three lines are in use}
(c) {at least three lines are in use}
(d) {between two and five lines, inclusive, are in use}
| x | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
| p(x) | 0.10 | 0.15 | 0.18 | 0.27 | 0.20 | 0.06 | 0.04 |
Solution
a)
Consider the table:
The last column if F(x) here, the asked cdf. [answer]
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b)
Fewer than 3 means at most 2. Hence,
P(fewer than 3) = F(2) = 0.43 [answer]
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c)
P(at least 3) = 1-P(fewer than 3) = 1 - 0.43 = 0.57 [answer]
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d)
As
P(between x1 and x2) = F(x2) - F(x1-1),
P(between 2 and 5) = F(5) - F(2-1) = 0.96-0.25 = 0.71 [ANSWER]
| x | P(x) | F(x) |
| 0 | 0.1 | 0.1 |
| 1 | 0.15 | 0.25 |
| 2 | 0.18 | 0.43 |
| 3 | 0.27 | 0.7 |
| 4 | 0.2 | 0.9 |
| 5 | 0.06 | 0.96 |
| 6 | 0.04 | 1 |
