Pls help with these questions Thankssss Assuming the frequen

Assuming the frequency of the Clock applied to the initial input (LSB at your right hand side) is 360 KHZ, what is the frequency of the output Q3-MSB(at your left hand side)? The counter from above is best described by: synchronous UP counter synchronous DOWN counter asynchronous UP counter asynchronous DOWN counter

Solution

Answer 8: When Enable is HIGH, all flip flips are in toggle mode.

Q0 will toggle with a frequency half of that of applied clock pulse. (f0 = f/2)

Q1 will toggle with a frequency half of that of output frequency of Q0. (f1 = f0/2)

Q2 will toggle with a frequency half of that of output frequency of Q1. (f2 = f1/2)

Q3 will toggle with a frequency half of that of output frequency of Q2. (f3 = f2/2)

Therefore frequency of Q3, f3 = f/16

f3 = (360/16) kHz = 22.5 kHz

Answer 9: c. asynchronous up counter

Asynchronous counter: except the first flip flop, every flip flop has its CP input connected to the output of the preceeding flip flop. so all the flips do not operate \'synchronously\' at the same time.

up counter: since the flip flops are triggering with negative edge and connected to complemented Q\' (i.e. equivalent to Q), it is up counter

Triggering with

CLK connection in

Access as

-ve edge / -ve level

Q

UP counter

-ve edge / -ve level

Q’

DOWN counter

+ve edge / +ve level

Q

DOWN counter

+ve edge / +ve level

Q’

UP counter

Triggering with	CLK connection in	Access as
-ve edge / -ve level	Q	UP counter
-ve edge / -ve level	Q’	DOWN counter
+ve edge / +ve level	Q	DOWN counter
+ve edge / +ve level	Q’	UP counter