All the data is the here 1 Write a hypothesis statement and

.All the data is the here.

1, Write a hypothesis statement and prediction from Table 1 (18.2)

2. Write a hypothesis statement and prediction from Table 2 (18.3)

3, Summarize your results from 18.2 (table 1) and 18.3. (table 2)

25 dominant 25 recessive 50 heterozygous (18.2) Table 1. Allele Frequency Allele Parent BB 28 Bb bb (18.3) Table 2. Allele Frequency in the presence 100% negative selection pressure Allele Generation 1 Generation 2 Generation 3 Generation 4 Generation 5 BB 22 33 30 38 38 Bb 39 30 27 25 Bb 23 (18.4) Table 3. Allele Frequency in the presence of 20% negative selection pressure already took 20% from bb Gene Generation 1 Generation 2 Generation 3 Generation 4 Generation 5 BB 21 34 26 Bb 34 53 51 bb 16 10

Solution

Ans 1.

Hypothesis statement from table 1: The given population is in Hardy-Weinberg equilibrium, and obeys law of independent assortment.

Ans 2.

Please note: There is a misprint in table 1. Instead of \'bb\', \'Bb\' is written.

Hypothesis statement is: In presence of 100% negative selection pressure, the genotype \'bb\' is lost from the population slowly and steadily.

Ans 3.

Table 1 results summary (18.2):

The genotype frequencies are in ratio (BB) 28: (Bb) 52: (bb) 20

This is showing 1:2:1 ratio given by Mendel. So, the population is in HW equilibrium.

Table 2 results summary (18.3):

In Generation 1, 1:2:1 is there.

Due to 100% negative selection pressure, \'bb\' genotype is removed from Generation 1.

So, for Generation 2, only ‘BB’ and ‘Bb’ cross with each other. Intercross between ‘Bb’ and ‘Bb’, still gives some \'bb\' genotypes. Again these are eliminated.

In Generation 3, \'BB\' and \'Bb\' of Generation 2 interbreed; reducing the genotype frequency of ‘bb’ still further.

By the time Generation 4 and 5 is reached, \'bb\' genotype is almost eliminated completely.