CHAPTER 5 INTRODUCTION TO GEOMETRY Find the perimeter of the

CHAPTER 5 INTRODUCTION TO GEOMETRY Find the perimeter of the figures in Exercises 37-40 37 9 in. 75 38 50 39. 60

(a) The perimeter of a sector of x^o is {2r + xr} / 180

{2r + xr} / 180 = {2 x 9 + 75 x 22/7 x 9} / 180 = 11.5 (approx.)

(b) In this case the figure is a combination of a square and a sector

Here r =5 as it will be equal to the side of square

{2r + xr} / 180 + 5 x 3 = {10 + 50 x 22/7 x 5} / 180 +15 = 810

(c) In this case the given figure is a combination of 2 isosceles right triangle and and 2 semi circles. Hence perimeter will be:-

4 x 41/8 + 2 x 22/7 x 11/4 = 37.7 (approx)