For the reaction AB if G o is negative what can you say abo

For the reaction A<-->B, if G o ’ is negative what can you say about the value of K eq ’ for this same reaction (1 sentence) ? (2 pts)

Solution

Keq > 1 Go\' has negative value, therefore reaction is possible.
Keq < 1 Go\' has positive value, therefore reaction is possible if [react] > [prod].
Keq >> 1 Go\' has large negative value, therefore reaction is irreversible.
Keq << 1 Go\' has large positive value, therefore reaction cannot occur.

delta G does not have to be zero in order for the reaction to be in equilibrium.

That means the above reaction will proceed to the right spontaneously, and at equilibrium, the concentration of the products will be greater than the concentration of the reactants.

If the concentration of the products are greater than the concentration of the reactants, than the nominator is greater than the denominator and thus Keq is greater than one.