The pressure and flow rate characteristics of a fan operatin
Solution
solution:
1)here for given fan characteristic equation relating head Hm and discharge V\' is given by
Hm1=.446+.0003*V\'-2.81*10^-7*V\'^-2+5.4105*10^-11*V\'^-3-3.5109*V\'^-4
2)where specific speed of fan is given by
Ns=N(V\')^.5/Hm^(3/4)
hence above is specific speed for this fan and it is same for all speed as it is geometric property .
for speed of N=1800 hz specific speed is
Ns=1800*(V\')^.5/Hm1^(3/4)
4)using same relation head for spped of N2=900 hz is
Hm2=(N/Ns)^(4/3)*V\'^(2/3)
putting value of Ns we get that
Hm2=.5^(4/3)Hm1=.3968*Hm1=.3968[.446+.0003*V\'-2.81*10^-7*V\'^-2+5.4105*10^-11*V\'^-3-3.5109*V\'^-4]
5)in same way head devloped for speed of N3=2400 Hz is
Hm3=(2400/1800)^(4/3)Hm1=1.4675Hm1=1.4675[.446+.0003*V\'-2.81*10^-7*V\'^-2+5.4105*10^-11*V\'^-3-3.5109*V\'^-4]
6)where power produced is given by
P1=density*g*V\'*Hm1
P1=density*g[.446V\'+.0003*V\'^2-2.81*10^-7*V\'^-1+5.4105*10^-11*V\'^-2-3.5109*V\'^-3]
7)here power related to P1 by
P2=P1(Hm2/Hm1)=.3968*P1=.3689[density*g[.446V\'+.0003*V\'^2-2.81*10^-7*V\'^-1+5.4105*10^-11*V\'^-2-3.5109*V\'^-3]]
P3=P1(Hm3/Hm1)=1.4675*P1=1.4675[density*g[.446V\'+.0003*V\'^2-2.81*10^-7*V\'^-1+5.4105*10^-11*V\'^-2-3.5109*V\'^-3]]
8)by using above formula we can easily get ploy for each case
