what am i doing wrong Sx J gx5x4 Solve for y0 2 2by4 K4Z 5x3

what am i doing wrong????

S(x) =J g(x)=5x+4 Solve for ($y)(0) +2 =-+2-by-4 K4Z -5x-3 SCO)-3 I- INH x /\\1 IX

Solution

f(x) = 1/sqrt(x+2) ; g(x) = 5x +4

(f -g)(0)

we need to find (f+g)(x) by adding the two functions

(f -g)(x) = 1/sqrt(x +2) -5x -4

plug x =0 (f +g)(x) = 1/sqrt2 -4

rationalizing the denominator :

sqrt 2 / 2 - 4

or (sqrt 2 - 8 )/ 2

1/2 ( sqrt 2 - 8)