To test H0 p 54 versus H1 muSolutionA critical value for al

Solution

A) critical value for alpha = 0.05 and d.f = 34 -1 = 33 ....is t ( 0.95 ,33) = 1.69236....

sample mean that separates the rejection region from the non rejection region is
= 54 - ( 1.69236 * 6 / sqrt ( 34) ) = 52.25858 = 52.3 ( rounded).........

B)  mean found in (a) = 52.3..actual mean is 52.8..

test statistic = ( 52.3 - 52.8) / ( 6 / sqrt ( 34 ) ) = -0.4859127.............

p-value = 0.6848799

beta = 0.6849..

power = 1- beta = 0.3151.....