Work out the algebra to solve for k in equation 4 in the man
Solution
Given you only want the equation to be resolved, I will take you through the step wise approach to do the same.
The equation we have here is:
1 / Ck = [1 / (koA/t)] + [1 / ( oA / d-t)]
We will arrange the right hand side to get:
1 / Ck = [t / (koA)] + [d - t / oA] [We have simply transferred the denominator of denominator to numerator]
As we need to single out K, I will transfer the first term on the right hand side to the left and bring 1 / Ck to the right and change the signs.
Then I will take LCM of the denominators on the right and add the fractions as follows:
t / (koA) = 1/Ck - [(d - t) / oA]
or t / (koA) = (oA - dCk + tCk )/ oACk
Now we can bring all the variables except k from the left hand side to the right to get:
1/ k = (oA - dCk + tCk )/ t*Ck
Take reciprocal of both the sides to obtain:
k = t*Ck /(oA - dCk + tCk )
Now, we know that Co = oA/ d, putting this in above equation, we get:
k = t(oA/ d) / oA - oA + (toA/d) = 1
Therefore, the equation as mentioned gives k = 1 fro Ck = Co
