Hello Can someone answer the all the questions here Im stuck

Solution

1. Airflow into the fuselage is approximately constant, and pressure is maintained by varying the opening of the \"out-flow valve\" (OFV). Pressure maintained in the cabin reduces as altitude increases.

2. Torque is directly proportional to friction and radial load. Friction is directly proportional to viscosity. As viscosity drops less torque is required to maintain same speed.

3. Flow is (area of pipe x velocity of flow x density). velocity = square root (2 x g x head). If head is increased 4 times, velocity should increase by more than 2. But in slurry, water is mixed with fine particles and hence frictional losses are much higher. Hence, mass flow rate is less than the theoretical 2 times.

4. At a depth of 15m, equivalent pressure is approximately 1.5 bar. Hence air consumed will be 1.5 x 130 = 195 litres. = 195 x 0.001cubic metres = 195 x 0.001x 1.225 kg = 0.2389 kg. As tank contains 3 kg of air, the fractio of air consumed is 0.2389 / 3 = 8%.