Sapling Learning understand the concept of static equilibriu

Sapling Learning understand the concept of static equilibrium a laboratory make a calculation before performing the experiment. The apparatus consists of a round level table in the center of which is a massless ring. There are three strings tied to different spots on the ring. Each string passes parallel over the table and is individually strung over a frictionless pulley (there are three pulleys) where a mass is hung. The table is degree marked to indicate the position or angle of each string. There is a mass m 0.161 kg located at 26.5 and a second mass m2 0.223 kg located at 62 287°. Calculate system and the ring will remain stationary Number m, kg Number

Solution

Given,

Mass, m₁ = 0.161kg., Weight, w₁= (0.161 x 9.81) = 1.58N.
Mass, m₂ = 0.223kg., Weight, w₂= (0.223 x 9.81) = 2.19N.
Let\'s \"rotate\" the table 26.5 degrees anticlockwise, so m₁ is at 0. That puts m₂ at (287 - 26.5) = 260.5 degrees.
(260.5 - 180) = 80.5 degrees \"west of south\".
South component of m₂ = (cos 80.5) x 2.19 = 0.36N.
West component = (sin 80.5) x 2.19, = 2.16N.
Subtract South component from weight m₁, = 1.58-0.36 = 1.22N., acting North.
Weight, w₃ = sqrt. (2.16^2 + 1.22^2), = 2.48N.,
Mass, m₃ = 2.48/9.81 = 0.253kg

Direction = arctan (1.22/2.16) = 29.46 degrees South of East.,
Now \"rotate\" the table back the 26.5 degrees clockwise, (26.5 + 29.46 + 90) = 145.96 degrees, is where to place the m3 of 0.253kg. (The \"90\" is because east is 90 deg. from North, and the 29.46 was from East).