Mimi just started her tennis class three weeks ago On averag

Mimi just started her tennis class three weeks ago. On average, she is able to return 20% of her opponent

Solution

X the number of returns that Mimi gets is binomial.

the events are independent and each trial has success chance p = 0.20

No of trials =8

Prob of failure q = 1-p = 0.80

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b) Probability that she returns atleast 1 of the 8 serves

= P(X>=1)

= 1-P(X=0) = 1-(0.8)8

= 0.8322

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c) Expected no of serves = Mean of binomial distribution = np

= 8x0.2 = 1.6

As 1.6 is a decimal we say that out of 40 serves on an average she returns 8 serves.

Mimi just started her tennis class three weeks ago. On average, she is able to return 20% of her opponentSolutionX the number of returns that Mimi gets is binom

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