Asoccer ball manufacturer wants to estimate the mean circumf
Solution
First, the z score to use for a 90% confidence interval is 1.645.
How this is obtained: If the confidence level is .90, alpha is .10 (1-.90), and alpha/2 would be .05. Looking up .05 on the standard normal table gives a z of 1.645.
a. The minimum sample size required to construct a 90% confidence interval using a population standard deviation of 0.25 inches is _____
The formula for the sample size required:
n = (z*sigma/E)^2.
z is 1.645.
sigma is 0.25
E is 0.05, the error given at the beginning of the problem.
Substituting these values:
n = (1.645*0.25/0.05)^2 = 68 (always round up)
answer: 68
b. The minimum sample size required to construct a 90% confidence interval using a standard deviation of 0.35 in is ______
The formula for the sample size required:
n = (z*sigma/E)^2.
z is 1.645
sigma is 0.35
E is 0.05
Substituting these values:
n = (1.645*0.35/0.05)^2 = 133 (always round up)
answer: 133
c. A population standard deviation of 0.35 in requires a larger sample size. Due to the increased variability in the population, a larger sample size is needed to ensure the desired accuracy.
