nicole de la torre 12615 742 P Quiz 73 Overview This Questio
Solution
1.
As the population is very skewed, and sample size is small (<30), then, we use t distribution.
Thus, for c = 0.90, then
alpha = (1-c)/2 = (1-0.90)/2 = 0.05
Thus, as df = n - 1 = 16 - 1 = 15, then by table/technology,
t(alpha/2) = 1.753 [ANSWER, D]
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2.
A)
Best point estimate = xbar = 151.81 [ANSWER]
b)
Note that
Margin of Error E = z(alpha/2) * s / sqrt(n)
Lower Bound = X - z(alpha/2) * s / sqrt(n)
Upper Bound = X + z(alpha/2) * s / sqrt(n)
where
alpha/2 = (1 - confidence level)/2 = 0.005
X = sample mean = 151.81
z(alpha/2) = critical z for the confidence interval = 2.575829304
s = sample standard deviation = 30.61
n = sample size = 40
Thus,
Margin of Error E = 12.46666856
Lower bound = 139.3433314
Upper bound = 164.2766686
Thus, the confidence interval is
( 139.3433314 , 164.2766686 ) [ANSWER]
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