Normally only 14 of the people who develop lung cancer survi

Normally only 14% of the people who develop lung cancer survive alter 5 years. Suppose you wanted to see if this survival rate is still true. How large a sample would you need to estimate the true proportion of survival after 5 years from diagnosis to within 1% with 96% confidence?

Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)
Z a/2 at 0.04 is = 2.054
Samle Proportion = 0.14
ME = 0.01
n = ( 2.054 / 0.01 )^2 * 0.14*0.86
= 5079.575 ~ 5080