To obtain information on the corrosionresistance properties
Solution
17.
We use z distribution, as n = 45 > 30.
Formulating the null and alternative hypotheses,
Ho: u <= 50
Ha: u > 50
As we can see, this is a right tailed test.
Thus, getting the critical z, as alpha = 0.05 ,
alpha = 0.05
zcrit = + 1.644853627
Getting the test statistic, as
X = sample mean = 52.7
uo = hypothesized mean = 50
n = sample size = 45
s = standard deviation = 4.8
Thus, z = (X - uo) * sqrt(n) / s = 3.773364712 =3.77
As z > 1.6449, we REJECT THE NULL HYPOTHESIS.
Hence,
OPTION C: YES, Z = 3.77 [ANSWER, C]
