The diagram shows the electric field lines due to two charge

The diagram shows the electric field lines due to two charged parallel metal plates. We conclude that: the upper plate is positive and the lower plate is negative a proton at X would experience the same force if it were placed at Y a proton at X experiences a greater force than if it were placed at Z a proton at X experiences less force than if it were placed at Z an electron at X could have its weight balanced by the electrical force An electron goes from one equipotential surface to another along one of the four paths shown below. Rank the paths according to the work done by the electric field, from least to greatest. 1, 2, 3, 4 4, 3, 2, 1 1, 3, 4 and 2 tie 4 and 2 tie, then 3, then 1 4, 3, 1, 2

Solution

(1). Electric field lines is start from positive and ends at negative.

So, lower plate id positive and upper plate is negative.

* In the diagram parallel lines indicates that the electric field is uniform.

So, the force on particle at X ,Y and Z points are equal.

(2). Work done W = potential difference x charge.

For 1 :

Potential difference dV = 80 V - 50 V = 30 V

So, work done = (30 V) q = 30 q   Where q = charge of the particle.

For 2 :

Potential difference dV = 80 V - 70 V = 10 V

So, work done = (10 V) q = 10 q   Where q = charge of the particle.

For 3 :

Potential difference dV = 80 V - 60 V = 20 V

So, work done = (20 V) q = 20 q   Where q = charge of the particle.

For 4 :

Potential difference dV = 80 V - 70 V = 10 V

So, work done = (10 V) q = 10 q   Where q = charge of the particle.

So, answer is 4 and 2 tie ,then 3 ,then 1