A random variable X is exponentially distributed with a mean
A random variable X is exponentially distributed with a mean of 0.16.
| a-1. | What is the rate parameter ? (Round your answer to 3 decimal places.) | 
Solution
a-1.
lambda = 1/mean = 1/0.16 = 6.25 [answer]
a-2.
standard deviation = mean = 0.16 [answer]
b)
The mean of the distirbution is also the standard deviation, and is equal to 1/lambda:          
           
 mean = standard deviation = 1/lambda =    0.16      
           
 The area between two values in an exponential distribution ois          
           
 Area = e^(-lambda*x)          
           
 As          
           
 x = critical value =    0.24      
           
           
 Then          
           
 Area =    0.22313016   [ANSWER]
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C)
  
 The mean of the distirbution is also the standard deviation, and is equal to 1/lambda:          
           
 mean = standard deviation = 1/lambda =    0.16      
           
 The area between two values in an exponential distribution ois          
           
 Area = e^(-lambda*x2) - e^(-lambda*x1)          
           
 As          
           
 x1 = lower bound =   0.09      
 x2 = upper bound =    0.24      
           
 Then          
           
 Area =    0.346652665   [answer]  

