If a die is rolled 35 times there are 635 different sequence
If a die is rolled 35 times, there are 635 different sequences possible. The following question asks how many of these sequences satisfy certain conditions.
What fraction of these sequences have exactly five 1s? (Round your answer to four decimal places.)
Solution
die is rolled 35 times,
so n=35
prob of 1, p= 1/6
prob. of non-one, q= 5/6
x:number of 1
P(x=5) = p^5 * q^30
P(x=5) = (1/6)^5 * (5/6)^30
P(x=5) = 5.42 * 10^(-7)
