Consider a 2000 N airplane with 50 m2 wingarea in a level cr
Solution
a) The lift is given by the relation,
L = 1/2 x rho x V^2 x A x CLalpha
Since the aircraft is banked at an angle of 10 deg the component of W reduces to W cos 10.
During ideal flight conditions the L = W,
1/2 x rho x V^2 x A x Cl alpha = m x cos 10
1/2 x 1.25 x 150^2 x 50 x CL alpha = 2000 cos 10 / 9.81
CL alpha = 2.85 x 10^-4
b) Since the flight maintains a level flight at the same altitude and under ideal conditions the load factor L / W is 1.
c) The required angle of attack for the ideal airfoil is given by,
CLalpha = 2 pi alpha,
So alpha = CL alpha / 2 pi
alpha = 2.85 x 10^-4 / 2 x 3.14 = 0.00004 rad or 0.002 deg
