Suppose the prices in Y1 Y2 Y3 YA of objects A B C and D are
Solution
a) We require find the probability that ,
P((3*Y1 + 4*Y2 + Y3)>30)
Now, we know that if X,Y,Z follows a multivariate normal distribution then any linear combination will follow a univariate normal distribution,
So take Z=3Y1+4Y2+Y3
And E(Z)=21, Var(Z)=222
Therefore, Z ~ N(21,222)
Now the required probability is,
P(Z>30))
=P((Z-21)/sqrt(222) >((30-21)/sqrt(222)))
=P(T>0.604), where T~ N(0,1)
=0.27426
b) Here Y1 follows a univariate normal distribution so the MGF is
M(t)=exp(t+1.5*t^2)
c) Here, Y1 and Y3 are jointly follows bivariate normal distribution,
So the mgf of Y1 and Y3 is,
M(t1,t2)=exp(t1 + 6*t2 +(3*t1*t1 + 9*t2*t2 + 2*3*t1*t2)/2)
d) Correlation(Y3,Y4)= cov(Y3,Y4)/sqrt(var(Y3)*Var(Y4))
Here, cov(Y3,Y4)=3
Var(Y3)=9, Var(Y4)=6
So the answer is 0.40824829
