What will be printed in the output and why include main in

What will be printed in the output? and why?

#include <stdio.h>

main( )

{

int a=3,b,d=12;

float c,f=7.2;

b=a++ * 2;

printf(\"%d %d\ \",a,b);

b=++a *2;

printf(\"%d %d\ \",a,b);

c = f+d/10 ;

f += d%8;

printf(\"%f %f\ \",c,f);

}

Solution

output is:

4 6

5 10

8.20000 11.20000

in first print statement : a=3,b=0 and d=12
b=a++ * 2;   

//intially b=0,a=3,d=12, b=a++ * 2 =>b=3*2 =>b=6 and
then a will become 4 beacuse a is post increment it first assign it cuurent value and then it
will increment
so here a=4 and b=6;

in second print statement : a=4,b=6 and d=12
b=++a *2;

//here a is pre increment it means it will first it value and then it will be assigned
so here a value is 4 so it will first increment to 5 ,b=5*2=>b=10
so here a=5 and b=10;

in third print statement : a=5,b=10 and d=12 ,c and f is float variable and f=7.2
c = f+d/10;
f += d%8;

here f=7.2 and d=12 acccording to bodmas rule first division will be done and then addition will done
so c=f+(12/10) =>as d is int it will cut decimal values so c=f+1 => c=7.2+1 =>8.20000

f+=d%8;=>here d=12 so f+ means it will increment it value by its assigned value that is
f+=12%8 => f+=4 =>as f value is 7.2 so it will increment 7.2 by value 4 that f=11.20000