Here are the red blood cell counts in 106 cells per microlit

Here are the red blood cell counts (in 10⁶ cells per microliter) of a healthy person measured on each of 15 days.

Find a 95% confidence interval estimate of ?, the true mean red blood cell count for this person during the period of testing. (Round your answers to three decimal places.)

5.3 5.2 4.9 5.3 5.5

5.2 5.5 5.3 5.2 5.2

5.3 4.8 5.4 5.2 5.1

sample mean=16.98333

sample standard deviation =0.3188521

sample size =15

The degree of freedom =n-1=15-1=14

Given a=1-0.95=0.05, t(0.025, df=14) =2.14 (from student t table)

So the lower bound is

xbar - t*s/vn =16.98333-2.14*0.3188521/sqrt(15)=16.807

So the upper bound is

xbar + t*s/vn =16.98333+2.14*0.3188521/sqrt(15)=17.160

Here are the red blood cell counts (in 106 cells per microliter) of a healthy person measured on each of 15 days. Find a 95% confidence interval estimate of ?,

Here are the red blood cell counts in 106 cells per microlit

Solution

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