Many has 35000 in a savings act earning 4 12 annual interes

Many has $3,5000 in a savings act earning 4 1/2 % annual interest that is compounded continuously. How much will be in the act after 3 years? log_4 2 log_9 (1/3) ln e^3 log_1/5 25 Sketch the graph f(x) = ln (x - 2) Write as a single logarithm with coefficient l log_2 X + 1/3 log_2 y - 3 log_2 Z

Solution

8) Compound interest continously :

Amount = Principal[e^(rate*time)]

= 35000[e^(0.045*3)]

=35000*1.144 = $ 40040

10) a) log4(2)

= log4/log2 = log2^2/log2 = 2*log2/log2

= 2

b) log9(1/3)

= log9/log(1/3) = log3^2/log3^-1

=2/-1

=-2

c) lne^3

= lne^3/lne

= 3lne/lne

= 3

d) log1/5(25) = log25/log(1/5)

= log5^2/log5^-1

= -2

14 ) 2log2(X) + 1/3log2y - 3log2z

use the property : logA -logB +logC = log(A*C)/B

=log2X^2 +log2(y^1/3) -log2(z^3)

= log2(x^2*y^1/3*z^3)

= log2(x^2*y^1/3*z^3)

 Many has $3,5000 in a savings act earning 4 1/2 % annual interest that is compounded continuously. How much will be in the act after 3 years? log_4 2 log_9 (1/

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