ted runs two thirds as fast as frank in two hours frank runs

ted runs two thirds as fast as frank. in two hours frank runs eight miles farther then ted. how fast does each run?

Solution

Ted data:
distance = d; rate = (2/3)x; time= 2 hr.
Frank data:
distance = d+8; rate = x; time = 2hr.
Formula: distance = rate*time
EQUATION:
Frank distance = Ted distance + 8
2x = (4/3)x+8
6x = 4x+24
2x = 24
x = 12 mph (rate for Frank)
(2/3)x= 8 mph (rate for Ted)