1 1 point Judys doctor is concerned that she may suffer from

1. (1 point) Judy\'s doctor is concerned that she may suffer from hypokalemia (low potassium in the blood). There is variation both in the actual potassium level and in the blood test that measures the level. Judy\'s measure potassium level varies according to the Normal distribution with = 3.8 and standard deviation

= 0.2. A patient is classified as hypokalemic if the potassium level is below 3.5

(a) If a single potassium measurement is made, what is the probability that Judy is diagnosed as hypokalemic?

Be sure to show the z-value you used and explain how you arrived at your answer for full credit.

(b) If Measurements are made instead on 4 separate days and the mean (average) result is compared with the criterion 3.5, what is the probability that Judy is diagnosed as hypokalemic?

Be sure to show the z-value you used and explain how you arrived at your answer for full credit.

1. (1 point) Judy\'s doctor is concerned that she may suffer from hypokalemia (low potassium in the blood). There is variation both in the actual potassium level and in the blood test that measures the level. Judy\'s measure potassium level varies according to the Normal distribution with = 3.8 and standard deviation

= 0.2. A patient is classified as hypokalemic if the potassium level is below 3.5

(a) If a single potassium measurement is made, what is the probability that Judy is diagnosed as hypokalemic?

Be sure to show the z-value you used and explain how you arrived at your answer for full credit.

(b) If Measurements are made instead on 4 separate days and the mean (average) result is compared with the criterion 3.5, what is the probability that Judy is diagnosed as hypokalemic?

Be sure to show the z-value you used and explain how you arrived at your answer for full credit.

Solution

1.
a)
X=3.8
Mean = 3.5
SD=0.2
n=1
z = ( X - Mean)/(SD/sqrt(n))
= (3.8 -3.5)/ (0.2/sqrt(1))
= 1.5

Therefore, from z table :
P-value = 0.9332 Answer

b)
X=3.8
Mean = 3.5
SD=0.2
n=4
z = ( X - Mean)/(SD/sqrt(n))
= (3.8 -3.5)/ (0.2/sqrt(4))
= 3

Therefore ,from z table :
P-value = 0.9987 Answer