IV A simple random sample of size n is drawn from a populati
Solution
(A) Given a=1-0.9=0.1, Z(0.05) = 1.645 (from standard normal table)
So the lower bound is
xbar - Z*s/vn =59.2-1.645*3.8/sqrt(45)=58.26816
So the upper bound is
xbar + Z*s/vn =59.2+1.645*3.8/sqrt(45)=60.13184
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(B)
So the lower bound is
xbar - Z*s/vn =59.2-1.645*3.8/sqrt(55)=58.35712
So the upper bound is
xbar + Z*s/vn =59.2+1.645*3.8/sqrt(45)=60.04288
Effect: The margin of error decreases.
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(C) Given a=1-0.99=0.01, Z(0.005) = 2.58 (from standard normal table)
So the lower bound is
xbar - Z*s/vn =59.2-2.58*3.8/sqrt(45)=57.73851
So the upper bound is
xbar + Z*s/vn =59.2+2.58*3.8/sqrt(45)=60.66149
Effect: The margin of error increases.
