solve initial value problem dxdy1sqrt x2 where y21 I am comp

solve initial value problem dx/dy=1/(sqrt x+2) where y(2)=-1

I am completely lost on this. Could you please show baby steps to finding the correct solution

dy=sqrt(x+2) dx put x+2=t ==>dx=dt dy=sqrtt dt y=2t^(3/2) /3 +c y=2(x+2)^(3/2) /3 +c y(2)=-1 ==>-1=16/3+c c=-19/3 y=2(x+2)^(3/2) /3 -19/3