The Mile High Travel MHT agency offers tours of downtown Den
Solution
a. Let the number of persons who take the tour be 25 + x. Then the price of the ticket p (x) = 305 - 8x.
b.The revenue R (x) = number of persons * ticket price = ( 25 + x) (305 - 8x) = 7625 + 105x - 8x2 ( however x 20 as the capacity of the tour bus is 45).
c. If R (x) is to be maximum, the dR/dx = 0 and d2R/dx2 should be negative. Here, dR/dx = 105- 16x. Thus if dR/dx = 0, then 105 -16x = 0 or, 16x = 105 so that x = 6.5625 = 7 ( on rounding off to the nearest whole number; howewver, for our satisfation, we woill check the value of R ( x) when x = 6 also). Also, d2R/dx2 = -16. Thus R (x ) is maximum when x = 7. Now, when x = 7, r (x) = (25 + 7) ( 305 -8*7) = 32( 305 - 56) = 32*249 = 7968. Also, when x = 6, R(x) = (25 +6)( 305 -8 *6) = 31* 257 = 7967. Thus, the maximum revenue from one tour is 7968.
d. The number of people on the maximum revenue tour will be 25 + 7 = 32 ( we may observe that 32 < 45).
3.The ticket price charged per person will be 305 - 8*7 = 305 - 56 = 249.
