One 10 ft Times 10 ft Times 10 ft room is filled with basket

One 10 ft Times 10 ft Times 10 ft room is filled with basketballs in a BCC arrangement, a second room with the same dimensions is filled with ping pong balls, also in a BCC arrangement. Which room has a greater amount of empty space? The room with ping pong balls The room with basketballs They both have the same empty space Can\'t tell without the dimensions of the balls Crystals structures for solids, BCC, FCC, HCP Do not change when the temperature is raised Can change with temperature without melting Must first liquefy before resolidifying with a different crystal structure Can never change volume, its solid, though the crystal structure can change The crystal structure for Zinc and titanium is FCC BCC Simple Cubic HCP A very large amount of cold working can be repeated if The part is tempered between cold working stages The deformation is very slow The yield point is not exceeded The part is annealed between cold working stages Aluminum has a Poisson ratio of 0.31 and Copper a ratio of 0.33, for the same elongation and initial diameters Aluminum will have a smaller diameter when elongated. Copper will have a smaller diameter when elongated. Can\'t determine without Young\'s modulus Can\'t determine without knowing the total length The same shear stress is applied to two identically shaped pieces of stainless steel and plain carbon steel. The stainless steel will distort more than the plain carbon. The stainless steel will distort less than the plain carbon. They will have the same distortion Can\'t be determined from the information

Solution

>> Solution 15

In BCC Arrangement, 68% space is occupied by the spherical atoms, irrespective of their size

So, in both cases, volume of empty space left will be same

>> Solution 16

Crystal structure can change on heating even the temperature does not reach their melting point

So, OPTION (b) is correct

>> Solution 17

According to arrangement of atoms in Zinc & Titanium,

crystal structure of Zn & Ti is HCP

So, Option (d) is correct

>> Solution 18

As due to tempering, teperature of workpiece is increased which is again decreased by doing further cold working

So, Option (a) is correct.