Find the exact value of the remaining sides of a 30 degree 6

Find the exact value of the remaining sides of a 30 degree -60 degree -90 degree triangle if the hypotenuse is square root of 3

let A= 30 degree ,B=60 degree ,C=90 degree

given hypotenuse is square root of 3

=>c=3

by law of sines a/sinA =b/sinB =c/sinC

a/sinA =c/sinC

a/sin30^o =3/sin90^o

a =(sin30^o)3/1

a =(1/2)3

a =3/2

a=0.866

b/sinB =c/sinC

b/sin60⁰ =3/sin90^o

b =sin60⁰3/1

b =(3 /2)*3

b =3 /2

b=1.5

remaining sides are 3 /2 =0.866, 1.5