Put each equation in standard exponential form y 23x y y

Put each equation in standard exponential form. y = 2(3^-x) y = y = 16^-x/2 y = y = pi^pi x y = y = 1(1/5)^3 + x/2 y = y = 3/0.245^2x - 7 y = (round values to four decimal places) y = 3(0.0004267)^-0.4 x + 2 y = (round values to seven decimal places)

Solution

a) y = 2 (3^-x)

y = 2/3^x

b) y = 16^-x/2

= (16^-1/2)^x

= [4^2(-1/2)]^x = 4^-x

= 1/4^x

c) y = pi^pi*x

= (pi^pi)^x

= (36.46)^x

d) y = (1/5)^(3+x/2)

= ((1/5)^3)(1/5)^(x/2)

= (1/125)[(1/5)^1/2]^x

= 0.008(2.236)^x