If 445 moles of an ideal gas occupies 635 liters at 431 K wh

If 44.5 moles of an ideal gas occupies 63.5 liters at 431 K, what is the pressure of the gas?

Use the equation PV=nRT

Rearranging to solve for P we get P=nRT/V

Now substitute

P=(44.5mol)(0.082057 L x atm/mol x K)(431K)/63.5L
n=44.5

R=0.082057 L x atm/mol x K

All of the units cancel out except atmospheres and solving we get

P=24.78atm