Homework Soursefx34x46x3240x21066 Increasing 160 and 10 infinity Decreasing
f(x)=(3/4)x^4+6x^3-240x^2-1066
Increasing (-16,0) and (10, infinity)
Decreasing (-infinity, -16) and (0,10)
Relative Min at x=-16 and x=10
Relative Max at x=0
Correct?
Increasing (-16,0) and (10, infinity)
Decreasing (-infinity, -16) and (0,10)
Relative Min at x=-16 and x=10
Relative Max at x=0
Correct?
Solution
for increasing f\'(x) = 3x^3 + 18x^2 - 480x > 0 x^3 + 6x^2 - 160x > 0 x(x+16)(x-10) > 0 incereasing in (10, infinity) and (-16,0) decreasing (-inifnty, -16) and (0,10) relative min when f\'x = 0 and f\"x <0 that is at x = -16 and 10 max at x =0 yeah all are correct :)
