aWrite sint in terms of cost Sint in quadrant III b Write ta

a)Write sin(t) in terms of cos(t)   Sin(t) in quadrant -III

b) Write tan(t) in terms of sec(t) :tan(t) in quadrant IV   

Solution

sin2 t + cos2t=1

sin2t=1-cos2t

sint= +-sqrt(1-cos2t)

and in third quadrant sin theta is negative

sin t=-sqrt(1-cos2t)

b. sec2t-tan2t=1

tan2t= sec2t -1

tan t= +-sqrt(sec2t-1)

In third quadrant tan theta is positive

Therefore tan t= sqrt(sec2t-1)

a)Write sin(t) in terms of cos(t) Sin(t) in quadrant -III b) Write tan(t) in terms of sec(t) :tan(t) in quadrant IV Solutionsin2 t + cos2t=1 sin2t=1-cos2t sint=

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