I dont need the work shown I just need the answers in the

Solution

1]a]

Work done by gravitational force at A= mgh_A=525kg*9.8m/s²*33m=169785J= 1.7*10⁵ J

b]

Work done by gravitational force at B= mgh_B=525kg*9.8m/s²*33/2m=84892.5J= -8.5*10⁴ J

c]

Work done by gravitational force on car from initial point to C= -1.7*10⁵ J

d]  At B= mgh_B=525kg*9.8m/s²*33/2m=84892.5J= 8.5*10⁴ J

e]  At A= mgh_A=525kg*9.8m/s²*33m=169785J= 1.7*10⁵ J

2]a]

Applied Horizontal force= 6.8N

Kinetic frictional force= 4.2N

F net= 6.8-4.2=2.6N

work done= F net* d= 2.6N* 0.80m= 2.08J

b] Increase in thermal energy= work done= 2.08J

3]a]

Change in Ke= 1/2m [V_f²- V_i²]=1/2* 4*10⁶[ 0²- (15*10³)²]= - 450*10¹² J= -4.5*10¹⁴ J

b]

1 Megaton of TNT= 4.2*10¹⁵J

Energy in Megaton TNT= 4.5*10¹⁴ J/4.2*10¹⁵J=0.107 Megaton TNT

c] Explosion over Hiroshima- 13 kilotons of TNT

1 Megaton of TNT= 4.2*10¹⁵J

Hence 1 Kiloton of TNT= 4.2*10¹² J

13 kilotons of TNT=13*4.2*10¹² J=54.6*10¹² J

Number of Hiroshima bombs= 4.5*10¹⁴ J/54.6*10¹² J=8.2

Number of Hiroshima bombs= 8 bombs