PrAB14 PrA15 and PrB35 1 PrBA 2 PrBA SolutionPA015 THEREF
Pr[A|B]=14, Pr[A]=15, and Pr[B]=35.
1. Pr[B|A] = ?
2. Pr[B|A] = ?
Solution
P(A)=0.15 THEREFORE P(A\') = 1-0.15 = 0.85
P(B\') = 0.35 THEREFORE P(B) = 1-0.35 = 0.65
P(A /B) = P(A B)/ P(B)
FROM THE QUESTION
0.14= P(A B)/0.65 THEREFORE P(A B) = 0.65*0.14 = 0.091
NOW P(B/A) = P(A B) / P(A) = 0.091/0.15 = 0.60
2) WE CAND FIND P(B/A\') UNLESS WE HAVE P(B U A\')
![Pr[A|B]=14, Pr[A]=15, and Pr[B]=35. 1. Pr[B|A] = ? 2. Pr[B|A] = ?SolutionP(A)=0.15 THEREFORE P(A\') = 1-0.15 = 0.85 P(B\') = 0.35 THEREFORE P(B) = 1-0.35 = 0.65 Pr[A|B]=14, Pr[A]=15, and Pr[B]=35. 1. Pr[B|A] = ? 2. Pr[B|A] = ?SolutionP(A)=0.15 THEREFORE P(A\') = 1-0.15 = 0.85 P(B\') = 0.35 THEREFORE P(B) = 1-0.35 = 0.65](/WebImages/3/prab14-pra15-and-prb35-1-prba-2-prba-solutionpa015-theref-970674-1761499518-0.webp)