The table below shows five baskets containing different quan

The table below shows five baskets containing different quantities of oranges.

(Baskets) Number of oranges (1) 30 (2) 18 (3) 30 (4) 33 (5) 36

(a) List all samples of size 2, and compute the mean of each sample.

(b) Compute the mean of the distribution of the sample mean and the population mean. Compare the two values.

(c) Compare the dispersion in the population with that of the sample mean.

Solution

(1) 30 (2) 18 (3) 30 (4) 33 (5) 36

The above are the no of mangoes in 5 baskets.

Samples of size 2 are given below

I. 30,30 Mean 30

II,. 30,18 Mean 24

III. 30, 33 Mean 31.5

IV. 30,36 Mean 33

V. 18,33 Mean 25.5

VI. 18, 36 Mean 27

VII. 33,36 Mean 34.5

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Mean of the mean = Sample average = Average of 30,24...34,5

= 29.357

Population mean = 29.4

(c) Measures of dispersion = Variance

= 13.41

The table below shows five baskets containing different quantities of oranges. (Baskets) Number of oranges (1) 30 (2) 18 (3) 30 (4) 33 (5) 36 (a) List all sampl

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