Consider a species with a normal diploid number of 2n 18 Fo

Consider a species with a normal diploid number of 2n = 18. For each of the following conditions, indicate how many chromosomes would be present in the somatic cell of an individual of this species. Haploid Triploid Tetraploid Trisomy Monosomy

Solution

Ploidy is the number of sets of chromosomes present in a cell. Ploidy is represented by n.
-If the diploid number of chromosomes (2n) =18, then the haploid number of chromosomes (n) = 9. The haploid number = diploid number(di=two) of chromosomes divided by two.

-tri=3 (so three times the haploid number)
3 times the number of the haploid (9x3) =triploid.

-tetra=4 (so four times the haploid number) 4 times the number of haploid (9x4) =tetraploid.

- trisomic (2n+1), I.e( 2×9 +1)= 19

-monosomic (2n-1), I.e( 2×9 -1)= 17