9 1 12x3x 275x2x SolutionWe have 514x3x212x3x297x2x22715x2x2

9 1 1-2x-3x 27-5x+2x

Solution

We have [(5-14x-3x2)/(1-2x-3x2)]*[(9+7x-2x2)/(27-15x+2x2)] = [(5/3-14x/3-x2)/(1/3-2x/3-x2)] *[(9/2+7x/2-x2)/ (27/2-15x/2+x2)] = [-(x+5)(x-1/3)/-(x+1)(x-1/3)]*[-(x+1)(x-9/2)/(x-6)(x-9/2)] =-[(x-1/3)/(x-1/3)]*[(x+5)/(x-6)]* [(x-9/2)/(x-9/2)]*[(x+1)/(x+1)] =-(x+5)/(x-6) = (x+5)/(6-x).

Note: We have used the quadratic formula for factorization e.g. (5-14x-3x2)= -(3x2+14x -5). Now as per the quadratic formula, the roots of x2+14x/3 -5/3 are [-14/3±(142/32-4*1*(-5/3)]/2*1 or, [-14/3±( 196/9+60/9)]/2 or, [-14/3±256/9]/2 or, (-14/3± 16/3)/2 i.e. 2/6 = 1/3 and -30/6 =   -5. Hence, 5/3-14x/3-x2 = -(x+5)(x-1/3). The same process has been used for factorizing the other polynomials.

 9 1 1-2x-3x 27-5x+2x SolutionWe have [(5-14x-3x2)/(1-2x-3x2)]*[(9+7x-2x2)/(27-15x+2x2)] = [(5/3-14x/3-x2)/(1/3-2x/3-x2)] *[(9/2+7x/2-x2)/ (27/2-15x/2+x2)] = [-

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