Write a java program Calculationjava to read integer numbers
Write a java program Calculation.java to read integer numbers from file and store them in an array. Then compute the alternating sum of all elements in an array. For example, if your program reads the input 1 4 9 16 9 7 4 9 11 then it computes 1 - 4 + 9 - 16 + 9 - 7 + 4 - 9 + 11 = 2 Create an input file Calculation.txt with following content: 1 4 9 16 9 7 4 9 11 Write a program named Calculation.java to perform the described function. Sample Output: Sample 1: The sequence is 1 - 4 + 9 - 16 + 9 - 7 + 4 - 9 + 11 = -2 The sum of sequence is -2 Sample 2: The sequence is 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 = 0 The sum of sequence is 0 Sample 3: The sequence is 10 - 5 + 2 - 6 + 8 - 7 + 3 = 5 The sum of sequence is 5
Solution
import java.io.*;
public class HelloWorld{
public static void main(String []args){
//declare required variables
BufferedReader br = null;
try {
String sCurrentLine;
int nos[]={};
//open file for reading
br = new BufferedReader(new FileReader(\"Calculation.txt\"));
//loop through EOF
while ((sCurrentLine = br.readLine()) != null) {
//read each line and pslit based on spaces
String token[]=sCurrentLine.split(\" \");
//convert each token into int and assign into array
nos=new int[token.length];
for(int i=0;i<token.length;i++)
{
nos[i]=Integer.parseInt(token[i]);
}
}
//delcre total variables
int total=nos[0];
//loop through array and find sum/difference
System.out.print(\"The sequence is \ \"+nos[0]);
for(int i=1;i<nos.length;i++)
{
if(i%2==0)
{
total+=nos[i];
System.out.print(\" + \");
}
else
{
total-=nos[i];
System.out.print(\" - \");
}
System.out.print(nos[i]);
}
//display result
System.out.println(\" = \"+total);
} catch (IOException e) {
e.printStackTrace();
}
}
}
